F(X+5)=x^2+3x+30

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Solution for F(X+5)=x^2+3x+30 equation: 



(F+5)=F^2+3F+30

We move all terms to the left:

(F+5)-(F^2+3F+30)=0

We get rid of parentheses

-F^2+F-3F+5-30=0

We add all the numbers together, and all the variables

-1F^2-2F-25=0

a = -1; b = -2; c = -25;
Δ = b2-4ac
Δ = -22-4·(-1)·(-25)
Δ = -96
Delta is less than zero, so there is no solution for the equation

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